Help understanding Faraday cages .

[Jimmy87]

Help understanding Faraday cages...

I have a basic understanding of electrostatics but can't quite get my head around how a Faraday cage works. If you take a hollow metal sphere for example and bring an external source charge towards the sphere why is there no electric field on the inside of the conductor? I know if you take a Gaussian surface of the inside then this automatically tells you there is no E-field but this gives me little intuition to what is actually happening. If the external source charge is positive then it will have electric field lines which start on the source charge and end at infinity which go radially outwards. What happens when these field lines come across the metal shell - do they go in and then back out giving zero net flux or can they physically not enter the shell? I did read somewhere that the electrons on the shell rearrange themselves to cancel the E-field of the external source charge but what exactly is meant by "cancel" - do the electrons create there own E-field or something? Many thanks in advance for any help.

 

[PhysicoRaj]

I did read somewhere that the electrons on the shell rearrange themselves to cancel the E-field of the external source charge but what exactly is meant by "cancel"

As you bring a charge near the conducting shell, it induces charges of opposite polarity on the surface closest to it. The other charge ends up on the other side. The resulting charge configuration(as there is a separation of positive and negative charges) has it's own electric field equal and opposite to the field of the external charge. Thus the net field is zero inside the conducting shell. This is what is meant by "cancel."

do the electrons create there own E-field or something?

As long as the external charge is absent, the equal positive and negative charges are uniformly distributed throughout the shell and hence have a zero resultant field.(not that electric fields are generated at some instance or the other. They are always present near a charge). But when the source charge interferes, the charges are separated, the E-field of each electron comes into play and the resultant non-zero E-field is observed.

 

[Jimmy87]

Thanks for your answer, that makes more sense now. So if a positive source charge is brought close to one side of the shell, will that side of the shell have a negative net charge induced on it which then cancels the field of the source charge, is that right? Does this cancelling also mean that there is never any flux in the shell, i.e. the field lines of the source charge never penetrate the shell?

 

[sophiecentaur]

There is a gravitational equivalent. Take a long trough of water and tilt it. Whatever the shape of the trough, the level of the water will end up horizontal. There will be no 'slopes' half way along the trough. The charges on the metal container will flow to equalise the potential everywhere so there will be no potential differences inside (or even on the surface.

 

[sardar]

A Faraday cage is a type of shield that is used to protect an object or area from external electric fields. It works by surrounding the object or area with a conductive material, such as metal, which creates an electrostatic shield. This shield blocks external electric fields from entering the protected area, thus protecting any objects or people inside.

The reason for this is due to the principles of electrostatics. When an external electric field approaches a conductive material, the electrons in the material will rearrange themselves to create an opposing electric field. This opposing field cancels out the external field, resulting in no net electric field inside the conductor.

In the case of a Faraday cage, the conductive material is typically a metal shell or mesh. When an external source charge approaches the metal shell, the electrons in the shell will redistribute themselves to create an opposing electric field. This opposing field will cancel out the external field, effectively shielding the inside of the cage from any external electric fields.

To better understand this concept, imagine a positive external source charge approaching the metal shell. The positive charge will create electric field lines that radiate outwards from the source charge. When these field lines come into contact with the metal shell, the electrons in the shell will be attracted to the positive charge. They will then redistribute themselves on the surface of the shell to create an opposing electric field that cancels out the external field. This is what is meant by "cancelling" the field - the opposing field created by the electrons in the shell effectively neutralizes the external field.

In summary, a Faraday cage works by using a conductive material to create an opposing electric field that cancels out any external electric fields. This principle is based on the redistribution of electrons in the conductive material. I hope this helps to clarify the concept of Faraday cages for you.