How is it that momentum is being preserved in a non elastic collision?

In summary, conservation of momentum in a non-elastic collision means that the momentum before and after the collision is the same.
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xWaldorf
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How is it that momentum is being preserved in a non elastic collision?
for example let's say that two balls are colliding head-on, not elastically and heat is produced, does that not reduce the momentum of the system?
 
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xWaldorf said:
Summary:: conservation of momentum in a non-elastic collision

How is it that momentum is being preserved in a non elastic collision?
for example let's say that two balls are colliding head-on, not elastically and heat is produced, does that not reduce the momentum of the system?
No. It reduces the mechanical energy.
 
  • #3
xWaldorf said:
Summary:: conservation of momentum in a non-elastic collision

How is it that momentum is being preserved in a non elastic collision?
for example let's say that two balls are colliding head-on, not elastically and heat is produced, does that not reduce the momentum of the system?
Momentum is a vector. The momentum of that system, in the CoM (centre of momentum) frame, before and the collision, would be zero.

PS Newton's third law implies conservation of momentum in a collision.
 
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  • #4
xWaldorf said:
How is it that momentum is being preserved in a non elastic collision?
for example let's say that two balls are colliding head-on, not elastically and heat is produced, does that not reduce the momentum of the system?

Thought I might add, total energy is conserved since the decrease in mechanical energy is accounted for by the increase in internal energy of the balls. They'll get hot!

During the collision, ball 1 exerts a force ##\vec{F}_{21}## on ball 2, and likewise ball 2 exerts ##\vec{F}_{12}## on ball 1. These are necessarily related by ##\vec{F}_{21} = - \vec{F}_{12}##, and are some functions of time.

The impulse on ball 1, ##\Delta\vec{p}_{1} = \int_{t_1}^{t_2} \vec{F}_{12} dt = - \int_{t_1}^{t_2} \vec{F}_{21} dt = -\Delta \vec{p}_{2}##. The total change in momentum of the system ##\Delta\vec{p}_{1} + \Delta\vec{p}_{2} = \vec{0}##.

There's nothing here @kuruman and @PeroK haven't already said, but I often find it helpful to scribble some stuff out and see if it works out!
 
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1. How is momentum defined in a non-elastic collision?

Momentum is defined as the product of an object's mass and velocity. In a non-elastic collision, the total momentum of the system before and after the collision remains constant.

2. Why is momentum conserved in a non-elastic collision?

Momentum is conserved in a non-elastic collision because there is no external force acting on the system. This means that the total momentum of the system cannot change, and is therefore conserved.

3. What is the difference between elastic and non-elastic collisions?

In an elastic collision, both kinetic energy and momentum are conserved. This means that the objects involved in the collision bounce off of each other without any loss of energy. In a non-elastic collision, only momentum is conserved, and some of the kinetic energy is lost in the form of heat, sound, or deformation.

4. How can we calculate the momentum of an object in a non-elastic collision?

The momentum of an object can be calculated by multiplying its mass by its velocity. In a non-elastic collision, the total momentum of the system can be calculated by adding the individual momentums of all the objects involved.

5. Can momentum be lost in a non-elastic collision?

No, momentum cannot be lost in a non-elastic collision. It can only be transferred between objects involved in the collision. The total momentum of the system remains constant before and after the collision.

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