- #1
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Hi.
I have been trying to calculate the real definite integral with limits 2π and 0 of ## 1/(k+sin2θ) ##
To avoid the denominator becoming zero I know this means |k|> 1
Making the substitution ##z= e^{iθ}## eventually ends up giving me a quadratic equation in ##z^2## with 2 pairs of roots given by ##z^2 = i (+\sqrt{k^2-1} - k ) ##
and ## z^2 = i (-\sqrt{k^2-1} -k ) ##
The solution then states that"clearly the 1st two poles lie inside the unit circle and the 2nd two outside". This seems reasonable but how do I know for a fact that it is true ?
Thanks
I have been trying to calculate the real definite integral with limits 2π and 0 of ## 1/(k+sin2θ) ##
To avoid the denominator becoming zero I know this means |k|> 1
Making the substitution ##z= e^{iθ}## eventually ends up giving me a quadratic equation in ##z^2## with 2 pairs of roots given by ##z^2 = i (+\sqrt{k^2-1} - k ) ##
and ## z^2 = i (-\sqrt{k^2-1} -k ) ##
The solution then states that"clearly the 1st two poles lie inside the unit circle and the 2nd two outside". This seems reasonable but how do I know for a fact that it is true ?
Thanks