Looking for an example of a random variable that does not have a prob density fn

In summary: CantorsDevilStaircaseFunction.html" In summary, a random variable with a probability density function has a Fourier transform known as a characteristic function. However, there are cases where a random variable does not have a probability density function, such as a mixed distribution with both discrete and continuous portions. In these cases, generalized functions (such as Dirac delta functions) can be used to represent an analog of a density and the random variable will still have a Fourier transform. However, there are also examples where a random variable does not have a well-defined density even in this weaker sense, such as the Devil's staircase function.
  • #1
seeker101
28
0
"If a random variable has a probability density function, then the characteristic function is its Fourier transform" - http://en.wikipedia.org/wiki/Characteristic_function_(probability_theory)#Definition".

I have never come across a random variable that did not have a probability density function. Can someone give an example of a random variable that does not have a probability density function?
 
Last edited by a moderator:
Mathematics news on Phys.org
  • #2
A mixed distribution corresponds to a random variable that is discrete over part of its domain and continuous over another part.

More technical: If a random variable is continuous, its distribution function is an absolutely continuous function, and doesn't have any jumps from the left:

[tex]
\sum_{x \in \mathcal{R}} [F(x) - F(x-)] = 0
[/tex]

Since F is absolutely continuous it has a derivative, which is the density.

On the other hand, if a random variable is discrete, every x with non-zero probability is an "atom", and

[tex]
\sum_{x \in \mathcal{R}} [F(x) - F(x-)] = 1
[/tex]

Here F does not have a density - the mass function is not, technically, the derivative of the cdf.

For a mixed distribution it is true that

[tex]
0 < \sum_{x \in \mathcal{R}} [F(x) - F(x-)] < 1
[/tex]

The cdf is a "mixture" of a continuous and discrete function; again, there is no density.
 
Last edited:
  • #3
Note however that even in this mixed case one can use generalized functions (distributions) in particular Dirac delta functions to write a pdf analogue. It will then also have a Fourier transform. Formally the Dirac delta function delta(x-a) is the derivative of a unit upward jump at a.

Here is, I think, a counter example.
Let the random variable X take on only rational values in the interval [0,1].

Recall the rational numbers are countable, i.e. you can index them with the natural numbers. Pick some random indexing of the rational values in [0,1], say x_1, x_2, ...
and let:
[tex]Pr(X=x_k) = 1/2^k[/tex]

[tex] \sum p_k = \sum_{k=1}^\infty 1/2^k = 1[/tex]

The distribution won't have a density function because the probabilities, though discrete are defined on a dense set in the unit interval. The cumulative probability will be Highly Discontinuous.
 
  • #4
jambaugh said:
Note however that even in this mixed case one can use generalized functions (distributions) in particular Dirac delta functions to write a pdf analogue. It will then also have a Fourier transform. Formally the Dirac delta function delta(x-a) is the derivative of a unit upward jump at a.

Here is, I think, a counter example.
Let the random variable X take on only rational values in the interval [0,1].

Recall the rational numbers are countable, i.e. you can index them with the natural numbers. Pick some random indexing of the rational values in [0,1], say x_1, x_2, ...
and let:
[tex]Pr(X=x_k) = 1/2^k[/tex]

[tex] \sum p_k = \sum_{k=1}^\infty 1/2^k = 1[/tex]

The distribution won't have a density function because the probabilities, though discrete are defined on a dense set in the unit interval. The cumulative probability will be Highly Discontinuous.
this is a discrete distribution - it is not mixed since there is no continuous portion.
 
  • #5
statdad said:
this is a discrete distribution - it is not mixed since there is no continuous portion.

Yes... and your point is?
 
  • #6
I took your post (given the topic of the OP) as a presentation of a mixed distribution. clearly I misunderstood the thrust of your message.
 
  • #7
statdad said:
I took your post (given the topic of the OP) as a presentation of a mixed distribution. clearly I misunderstood the thrust of your message.

Ahhh, I see. To my mind even a discrete distribution (within a continuous space such as the reals) has a pdf in the more general sense of a distribution rather than a true function, by utilizing delta functions one may be able to handle the discrete components. So a purely discrete or a mixed may have a pdf. However as with my example you can cook up a random variable with well defined probabilities but due to topological issues no well defined pdf even in the weaker sense I'm using. However upon thinking about you can probably still work with delta functions (at least formally) in my example and even define a Fourier transform of it. My counter example may not be a counter example in this weaker sense.

I'll have to think about it.
 
  • #8
I've never seen delta functions used as to represent analogs of densities - the measure theory based stat and probability courses I took used the typical approach (Lebesgue-Stieltjes integrals, etc) exclusively (I assume you're well aware of this, so please don't take this as a "lecture" or "talking down".)

As a final comment, if you haven't seen it, there is a very interesting, widely used, construction of a singular continuous distribution on the Cantor set. (Pages 12-13 of Chung, second edition, is one source).

No more from me, however, as it is likely I have already gone too far astray from the question in the OP's first post.
 
  • #9
EDIT: just saw now the final comment of Statdat's post; I believe this is what is referring to.

One example would be a random variable with the devil's staircase (or Cantor's function) as a distribution function. For a description see:

http://en.wikipedia.org/wiki/Cantor_function"

It's a continuous function, differentiable almost everywhere, with a null derivative (almost everywhere). Therefore, it doesn't have a pdf, not even in a generalized sense.
 
Last edited by a moderator:
  • #10
statdad said:
I've never seen delta functions used as to represent analogs of densities - the measure theory based stat and probability courses I took used the typical approach (Lebesgue-Stieltjes integrals, etc) exclusively (I assume you're well aware of this, so please don't take this as a "lecture" or "talking down".)
My understanding of the delta function is that, as it is not a true function, it is only meaningful as a distribution.

As a final comment, if you haven't seen it, there is a very interesting, widely used, construction of a singular continuous distribution on the Cantor set. (Pages 12-13 of Chung, second edition, is one source).
That would be the "Devil's staircase"? I recall it from Real Analysis some time back as an exotic example of a continuous function useful for many counter examples.

Edit: Here's its pic on Wolfram Math:
DevilsStaircase_1000.gif
 

Related to Looking for an example of a random variable that does not have a prob density fn

1. What is a random variable?

A random variable is a numerical quantity that takes on different values based on the outcome of a probability experiment. It is often denoted by the letter X and can have discrete or continuous values.

2. What is a probability density function?

A probability density function (PDF) is a mathematical function that describes the probability distribution of a random variable. It gives the probability of a specific value occurring within a range of values.

3. Can you provide an example of a random variable without a probability density function?

Yes, a common example is the outcome of a coin toss, where the random variable is the number of heads obtained. In this case, the random variable can only take on discrete values (0 or 1) and does not have a probability density function.

4. Why is it important to have a probability density function for a random variable?

The probability density function allows us to calculate the probability of a specific value or range of values occurring for a random variable. This is essential for understanding and analyzing the behavior of the random variable in a probability experiment.

5. Are there any other examples of random variables without a probability density function?

Yes, any discrete random variable, such as the outcome of rolling a die or the number of red cars passing by, does not have a probability density function. Only continuous random variables have a probability density function.

Similar threads

  • Set Theory, Logic, Probability, Statistics
Replies
1
Views
233
  • Set Theory, Logic, Probability, Statistics
Replies
4
Views
912
  • Set Theory, Logic, Probability, Statistics
Replies
11
Views
618
  • Set Theory, Logic, Probability, Statistics
Replies
6
Views
4K
  • Calculus and Beyond Homework Help
Replies
2
Views
1K
Replies
1
Views
2K
  • General Math
Replies
4
Views
2K
Replies
8
Views
2K
Replies
1
Views
2K
  • Quantum Physics
Replies
3
Views
672
Back
Top