More slits, farther maxima of interference patterns, why?

The intensity is also proportional to the square of the amplitude of ## E ## which is related to the amplitude of the ## B ## field, and the power is proportional to the square of the amplitude of the ## E ## field. ## \\ ##In summary, when observing interference patterns, the maxima from a double slit are more intense and farther apart than those of a single slit. The same applies to the maxima of a diffraction grating, which are even more intense and farther apart than those of a double slit. This is because the primary maxima, where constructive interference occurs, are very intense and have very little intensity outside of them. Additionally, the intensity at the maxima for a diffraction grating is proportional
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Cardinalmont
When observing interference patterns, one will notice that the maxima from a double slit are more intense and farther apart than the maxima of a single slit. Likewise, the maxima from a diffraction grating are more intense and farther apart than maxima of a double slit. Why is this?

I understand that the minima are created when light with a phase difference of half a wavelength interact with each other, and more slits means more opportunity for half a wavelength phase changes, but doesn't it also present more opportunity for light of different phase shifts to hit those spots? Wouldn't it also present more opportunities for everything, not just minima?

I ask because I put a red laser pointer through a diffraction grating and the maxima were extremely far apart and extremely distinct! Unbelievable!
 
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For the two slit case as well as the multi-slit or multi-line case, the important thing is the primary maxima, where constructive interference occurs at ## m \lambda =d \sin{\theta} ## with ## m ##=integer. Whether it is just two slits or many equally spaced slits, the primary maxima for a given ## d ## occur in the same place. When you shine a laser onto a grating, it is likely you used ## N=100 ## or more of the slits at the same time. When they are equally spaced, if slit 1 constructively interferes with slit 2, and slit 2 constructively interferes with slit 3, then you can say all of them constructively interfere. The same logic applies, even if you have 100 or more slits. In the case of many slits, the many slits generally have a cancellation effect for the most part, anywhere that they do not constructively interfere, (unlike the two slit case where the maxima are rather broad), so that the primary maxima are very intense, and very little intensity outside of them. In addition, because the intensity is proportional to the square of the electric field, the intensity at the maxima for the case of a grating will be proportional to ## N^2 ##. The fact that the diffraction grating can put a specific wavelength at a very specific location makes it very useful in making spectral measurements. ## \\ ## I could also add a little about the single slit diffraction pattern: The most important feature there is the width of the central maximum, where the first zeros from the center peak occur for ## m=+1 ## and ## m=-1 ## at location ## m \lambda =b \sin{\theta} ##. The same diffraction/interference principles are responsible for the single slit diffraction pattern that cause the multi-slit interference. For multi-slit interference, oftentimes narrow slits are used , making a wide pattern, so the diffraction from individual slits can often be ignored in the multi-slit interference. ## \\ ## The derivation of the single slit pattern uses a continuum of sources across the slit where the phase ## \phi ## is a function of position inside the slit. (## \phi=\phi(x)=\frac{2 \pi x \sin{\theta}}{\lambda} ## ). The sources are added together (i.e. the electric fields from each in the far-field are superimposed) in integral form. The source at location ## x ## is ## E_o \cos(\omega t +\phi(x)) \, dx ##. ## \\ ## Meanwhile, the multi-slit interference pattern uses point sources that have a phase ## \phi ## that also depends on their location: ## \phi_n= \frac{2 \pi (n-1)d \sin{\theta}}{\lambda} ## where ## n ## is the slit number for a given slit. The sources for this case are summed with an arithmetic sum. The source for a given slit is ## E_o \cos(\omega t+\phi_n ) ##. ## \\ ## In both cases, the intensity ## I(\theta) ## (in watts/m^2) is proportional to the square of the amplitude of the resultant ## E ## field.
 
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1. Why do more slits result in farther maxima in interference patterns?

The distance between the maxima in an interference pattern is directly related to the wavelength of the light and the distance between the slits. When there are more slits, the distance between them decreases, causing the maxima to be farther apart.

2. How does increasing the number of slits affect the overall interference pattern?

Increasing the number of slits in an interference pattern creates more peaks and valleys, resulting in a more complex interference pattern. This is because each slit creates its own individual pattern, which then overlaps with the patterns from the other slits.

3. Is there a limit to how many slits can be used in an interference pattern?

Technically, there is no limit to the number of slits that can be used in an interference pattern. However, as the number of slits increases, the pattern becomes more complex and difficult to distinguish.

4. How does the distance between the slits affect the interference pattern?

The distance between the slits determines the spacing of the maxima and minima in the interference pattern. As the distance between the slits increases, the maxima become closer together and the minima become farther apart.

5. Can different colors of light produce different interference patterns with the same number of slits?

Yes, different colors of light have different wavelengths, which can result in different interference patterns with the same number of slits. This is because the distance between the maxima in an interference pattern is directly related to the wavelength of the light.

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