- #1
victorvmotti
- 155
- 5
Consider the infinite dimensional vector space of functions ##M## over ##\mathbb{C}##.
The inner product defined as in square integrable functions we use in quantum mechanics.
If we already know that the orthogonal complement is itself closed, how can we show that the orthogonal complement of the orthogonal complement gives the ***topological closure*** of the vector space and not the vector space itself?
$$M^{{\perp}{\perp}}=\overline M$$
The inner product defined as in square integrable functions we use in quantum mechanics.
If we already know that the orthogonal complement is itself closed, how can we show that the orthogonal complement of the orthogonal complement gives the ***topological closure*** of the vector space and not the vector space itself?
$$M^{{\perp}{\perp}}=\overline M$$
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