- #1
Mr Davis 97
- 1,462
- 44
The following is invalid, since the operation is not defined when ##a, b < 0##: ##\sqrt{-1}\sqrt{-1} = \sqrt{(-1)(-1)} = \sqrt{(-1)^2} = \sqrt{1} = 1##. This is not correct, because ##ii = -1##. This shows that ##\sqrt{a}\sqrt{b} = \sqrt{ab}## is invalid when ##a, b< 0##.
However, say we have ##\sqrt{-5}##. In order to simplify this, we do the following: ##\sqrt{-5} = \sqrt{(-1)(5)} = \sqrt{-1}\sqrt{5} = i\sqrt{5}##. Why is this a valid manipulation given the previous statement that ##\sqrt{a}\sqrt{b} = \sqrt{ab}## is invalid when ##a, b< 0##?
However, say we have ##\sqrt{-5}##. In order to simplify this, we do the following: ##\sqrt{-5} = \sqrt{(-1)(5)} = \sqrt{-1}\sqrt{5} = i\sqrt{5}##. Why is this a valid manipulation given the previous statement that ##\sqrt{a}\sqrt{b} = \sqrt{ab}## is invalid when ##a, b< 0##?