- #1
mikemichiel
- 7
- 0
Im givin these two lines..
L1= x=4+5t y=5+5t z=1-4t
L2= x=4+s y=-6+8s z=7-3s
What i tried doing was taking the directional vector of both lines <5 5 -4> <1 8 -3>, and crossing them to find the normal vector. I hav enough information to find 1 equation of a plane, but how can I find the other. Can someone please point me in the right direction. Thanks in advance!
L1= x=4+5t y=5+5t z=1-4t
L2= x=4+s y=-6+8s z=7-3s
What i tried doing was taking the directional vector of both lines <5 5 -4> <1 8 -3>, and crossing them to find the normal vector. I hav enough information to find 1 equation of a plane, but how can I find the other. Can someone please point me in the right direction. Thanks in advance!