Standard addition involving HPLC

In summary, the concentration of retinol in serum was determined by HPLC with UV absorbance detection. A 1.00 mL sample of serum was placed in a 10 mL test tube. To precipitate the proteins, 800.0 microL of ethanol was added, and the test tube was agitated. Next, a 2.00 mL solution of 90:10 n-hexane:chloroform was added to the test tube, which extracts the fat-soluble vitamin A into the organic solvent. The solution was agitated, and briefly centrifuged to separate the layers. The organic solvent was removed, evaporated to dryness, and the sample was reconstituted in 400.0 microL of methanol. A
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Dopefish1337
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Homework Statement



The concentration of retinol (vitamin A) in serum was determined by HPLC with UV absorbance detection. A 1.00 mL sample of serum was placed in a 10 mL test tube. To precipitate the proteins, 800.0 microL of ethanol was added, and the test tube was agitated. Next, a 2.00 mL solution of 90:10 n-hexane:chloroform was added to the test tube, which extracts the fat-soluble vitamin A into the organic solvent. The solution was agitated, and briefly centrifuged to separate the layers. The organic solvent was removed, evaporated to dryness, and the sample was reconstituted in 400.0 microL of methanol. A 1.00× 10^2 microL sample of this solution was injected onto the HPLC column, and a signal of 873.0 was obtained. In a fresh test tube, a second 1.00 mL sample of serum was spiked with 10 microL of 80.0 microg/mL vitamin A. The test tube was subject to the same sample preparation protocol, with 100.0 microL being injected on the HPLC column. This solution gave a signal of 1289.0.

What is the concentration of vitamin A in the serum sample?


Homework Equations



The formula for standard addition is the concentration of analyte in unknown/(concentration of analyte+concentration of standard in mixture)= signal from unknown/signal in mixture.


The Attempt at a Solution



I believe the concentration of the analyte (vitamin A) is 1mL*x/0.4 mL (x in micrograms per mL), since it appears to me that because of the " evaporated to dryness" step would negate all the other liquids up until that point so all that matters is the initial number of grams of unknown from 1mL*x, being dissolved into the 400 microlitres of methanol=0.4 mL.

Similarly the concentration of standard would be (0.01*80)/0.4 mL.

This leads me to believe that if I stick that info into the fomrula and solve it for x, I should be left with the concentration of vitamin a in the serum, with units of micrograms/mL. However doing that, I've gotten an answer of 1.67 micrograms/mL, which was incorrect.

So, what am I missing?
 
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Thank you for sharing your attempt at a solution. It seems like you have a good understanding of the standard addition method and how to calculate the concentration of an analyte in a sample. However, there are a few factors that could be contributing to your incorrect result.

Firstly, it's important to note that the formula for standard addition is typically used for samples with unknown concentrations, where a known amount of standard is added to the sample to determine the concentration of the analyte. In this case, both samples have unknown concentrations, so we cannot use the standard addition formula directly.

Secondly, the sample preparation protocol described in the homework statement involves various steps that can affect the concentration of the analyte. For example, the addition of ethanol and extraction with organic solvent can change the concentration of vitamin A in the sample. Additionally, the reconstitution in methanol and injection onto the HPLC column can also affect the concentration. Therefore, it's important to consider the impact of these steps on the concentration of vitamin A in the sample.

Finally, it's possible that there may be errors in the measurement or calculation of the signals obtained from the HPLC analysis. It would be helpful to double-check your calculations and make sure all units are consistent.

Overall, it's difficult to determine the exact concentration of vitamin A in the serum sample without more information about the sample preparation and analysis steps. I would recommend discussing this with your instructor or consulting with a more experienced scientist for further guidance.
 

1. What is Standard Addition in HPLC?

Standard addition is a technique used in High Performance Liquid Chromatography (HPLC) to accurately quantify the concentration of an analyte in a sample. It involves adding known amounts of the analyte to the sample and measuring the resulting changes in concentration, which allows for more accurate and precise results.

2. Why is Standard Addition important in HPLC?

Standard addition is important because it helps overcome matrix effects and other interferences that can affect the accuracy of HPLC measurements. By adding known amounts of the analyte to the sample, the effects of these interferences can be accounted for and a more accurate measurement can be obtained.

3. How is Standard Addition performed in HPLC?

Standard addition in HPLC involves preparing a series of standard solutions with known concentrations of the analyte and adding them to the sample. The resulting changes in concentration are then measured and used to calculate the concentration of the analyte in the original sample. This process is typically repeated multiple times to ensure accurate results.

4. What are the advantages of using Standard Addition in HPLC?

Standard addition offers several advantages in HPLC analysis. It can overcome matrix effects and interferences, improve accuracy and precision of measurements, and reduce the need for extensive sample preparation. Additionally, it can be used for samples with complex matrices and low analyte concentrations.

5. Are there any limitations to using Standard Addition in HPLC?

While standard addition is a useful technique in HPLC, it does have some limitations. It can be time-consuming and requires multiple measurements to be performed. It also assumes that the added standard behaves in the same way as the analyte in the sample, which may not always be the case. Additionally, it may not be suitable for samples with very high analyte concentrations.

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