Translational and rotational kinetic energy-Mass Unknown

AI Thread Summary
A hollow, thin-walled sphere with a mass of 20 kg rolls down a 30° incline, covering 20 m in 3.6 seconds, prompting the need to determine the mass of an unknown liquid inside. The discussion emphasizes the importance of translational and rotational kinetic energy, noting that the center of mass velocity is independent of mass and radius. Participants suggest calculating acceleration and treating the liquid as non-rotating while considering the moment of inertia provided. There is a debate on whether to differentiate between the thin-walled sphere and a solid sphere filled with liquid. The focus remains on using the given parameters to solve for the liquid's mass effectively.
Crusader711
Messages
5
Reaction score
0
A hollow, thin-walled sphere (ICM = 2MR2/3) of mass 20 kg is completely filled with a liquid of unknown mass. The sphere is released at the top of a plane inclined at 30° to the horizontal, and it rolls 20 m to the bottom in 3.6 s. What is the mass of the liquid?



2.My approach is translational and rotational kinetic energy, first off. I know that for rolling spheres the v-cm is not dependent upon the mass nor radius of the objects. So I come up with a translational speed but I'm not certain where to go from there. But the problem wants the mass of the liquid. I have two different sphere's in theory, a solid and a thin-walled version.



3. Looking for a lead into the next step...
 
Physics news on Phys.org
Hi Crusader711! :smile:
Crusader711 said:
I know that for rolling spheres the v-cm is not dependent upon the mass nor radius of the objects.

for a particular shape, yes
I have two different sphere's in theory, a solid and a thin-walled version.

But you're given the moment of inertia anyway.

Since we're not told the radius of the sphere, I think we're supposed to assume that the liquid does not rotate.

So find the acceleration, call the mass of the liquid "m", and carry on from there. :smile:
 
Rolling verses Frictionless

Would we treat the spheres differently?

thin-walled sphere rolling...

...then solid sphere with liquid, liquid sphere moving down incline (not rolling), but we have to account for the ICM of the thin-walled shell too?

Any thoughts?
 
(just got up :zzz:)

i assume "ICM" means moment of inertia?

you are given the moment of inertia and the mass, why do you need to know anything else?
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top