What ions produce a 2.00 V potential in an electrochemical cell?

AI Thread Summary
To achieve a potential close to 2.00 V in an electrochemical cell, the suggested ions are Fe3+ to Fe2+ with a reduction potential of -0.771 V and Na(s) to Na+ with a potential of +2.71 V. The calculated cell voltage using these reactions results in 1.94 V. The discussion highlights the importance of understanding how to combine the voltages of the half-reactions correctly. Clarification on the signs of the voltages is also sought, emphasizing the need for accurate calculations in electrochemistry.
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Homework Statement


Based on the following chart, what ions would you use to construct an electrochemical cell with potential closest to 2.00 V?

[PLAIN]http://img546.imageshack.us/img546/5568/electrochemicalcellchar.png

Homework Equations


I know that I am supposed to add the voltages of the 2 reactions but I am not sure how the signs would go. We are not using a textbook for this class so I have nothing to reference.


The Attempt at a Solution


I'd use the following reactions and voltages
Fe3+ -> Fe2+ (-0.771 gaining electron)
Na (s) -> Na+ (+2.71 losing electron)

so the cell voltage would be 1.94V. Is this correct?
 
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Think about simple math - what is the distance between -2.7 and +0.7 points?
 
Thank you, that was very helpful!
 

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