What is the 5th term of the expansion of $(2x+7)^8$ using the Binomial Theorem?

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In summary, the 5th term of $(2x+7)^8$ can be found using the binomial theorem, which states that the $m$th term of the expansion is given by $m=k+1$, where $k$ is the index of the term. In this case, the 5th term corresponds to $k=4$, giving us the result of $2689120x^4$.
  • #1
karush
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Find the 5th term of $(2x+7)^8$

Assume Binomial Theorem can be used on this.
not sure what determines the 5th term
 
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  • #2
karush said:
Find the 5th term of $(2x+7)^8$

Assume Binomial Theorem can be used on this.
not sure what determines the 5th term

Yes, the binomial theorem is your friend here...and it states:

\(\displaystyle (a+b)^n=\sum_{k=0}^n\left({n \choose k}a^{n-k}b^k\right)\)

And so the $m$th term of the expansion would be for $m=k+1$...can you proceed?
 
  • #3
${5}^{th}$ term =
$$2689120{x}^{4}$$

😍😍😍
 
  • #4
I get:

\(\displaystyle {8 \choose 4}(2x)^{8-4}(7)^4=70\cdot16x^4\cdot7^4=2689120x^4\checkmark\)
 
  • #5
If this was on the exam, some students could multiply 2x + 7 itself 8 times and get the desired result.
Hopefully, the student has studied the binomial theorem before the exam!
 

Related to What is the 5th term of the expansion of $(2x+7)^8$ using the Binomial Theorem?

1. What is the formula for finding the 5th term of (2x+7)^8?

The formula for finding the nth term of a binomial expansion is (a+b)^n = nCr(a^n)(b^(n-r)), where n is the power, r is the term number, and a and b are the coefficients. In this case, a = 2x and b = 7.

2. How do I determine the value of r for the 5th term?

In this case, r = 5 because we are looking for the 5th term. This number will change for different terms, so make sure to double check which term you are looking for.

3. Can I use a calculator to find the 5th term?

Yes, you can use a calculator to find the 5th term. You will need to use the formula mentioned in question 1 and input the values for a, b, n, and r. Make sure to use parentheses to avoid any calculation errors.

4. What is the coefficient of the 5th term?

The coefficient of the 5th term is the number in front of the variable. In this case, the coefficient is (8C5)(2^3)(7^3) = 56(8)(343) = 153664.

5. Is there a shortcut method for finding the 5th term?

Yes, there is a shortcut method called the Pascal's Triangle method. This method involves finding the corresponding row in the Pascal's Triangle for the power of the binomial, in this case, the 8th row. The numbers in this row represent the coefficients for each term, and the 5th term would be the 5th number in this row, which is 153664.

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