Word force and friction problem

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To solve the problem of pulling a sled with a cousin on it, the total mass to consider is 25 kg, combining the sled's mass of 15 kg and the cousin's mass of 10 kg. The force applied is 200 N at a 50-degree angle, which affects the net force calculation due to the angle and friction. The coefficient of static friction is 0.2, which will impact the acceleration when included in the calculations. The discussion emphasizes the importance of understanding how to account for both the combined mass and the frictional force when determining acceleration. Proper application of physics equations is crucial for finding accurate results in this scenario.
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Homework Statement


I am pulling my cousin who has a mass of 10kg, geets all bundled up and sits in the sled, which has a mass of 15kg. He yells ready,set,go and I start to pull him across the snow. I am pulling the sled at an angle of 50degrees with respect to the horizontal. Assume that the coefficient of static friction between the sled and the snow is Ms=.2 if I pull him across the snow with a force of 200N, fine the following values.

A) Find the acceleration of my cousin and the sled without friction
B)find acceleration with friction included



Homework Equations





The Attempt at a Solution

 
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You have to start this out by showing an attempt and explaining what is confusing you about the problem or by giving some appropriate formulas and explaining why you can't even start.
 
I can find the answers, but I have a question about finding the acceleration of the cart. When it asks me to find the acceleration of the car with the cousin inside it does that mean the carts weight+kids weight?
 
You are pulling both the kid and the sled. Yes, add their masses.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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