Originally posted by lethe
so are you saying that the phase of the wavefunction of a spin 2 particle returns to its starting point after a 180 degree rotation? hmm... let me think about that. if that is true, i didn t know that.
but my point here was, the angular momentum vector of a spin 2 particle will be pointing the opposite way after a 180 degree rotation, and requires a 360 rotation to come back to where it started.
the same will be true of any spin j particle for j an integer. (and 720 degrees for any half integer)
well, i hear all the time that spin half particles just defy all intuition, and to that i make two objections:
1. there are classical configurations that you can make that can easily demonstrate that you really need 720 degrees, so this doesn t really hinge on half integral spin.
2. the real difference after a 360 degree rotation is only a difference in phase, and i claim that no one has any intuition about phase anyway. so insofar as anyone has any intuition about quantum mechanical objects (with arbitrary spin), that intuition is still valid for spin 1/2 objects as well.
but this is just my opinion against the party line of the textbooks, so i don t mean to be picking on you on this point. and feel free to disagree.
I'll do my best with what little time I have right now to give some basic examples. I think I'll demonstrate this using the first spin-triplet set of mesons, specifically the lighter isosinglets. They'll be a good example because they have the same angular momentum and spin momentum numbers, but couple to different values of J. So, we start with:
the scalar meson
f0(1370)
the pseudovector meson
f1(1285)
the tensor meson
f2(1270)
All three have L = 1, S = 1, and positive parity, but span the set of multiplets J
P = {0
+,1
+,2
+}. First,
f0(1370) has spin and angular momentum coupling to J = 0. It can be viewed as having the angular momentum vector and spin momentum vector being equal and opposite at all times, so that the net result is zero no matter how you "turn" them in phase space. Therefore, no matter how small you make d\theta, the particle will always "look" the same (have the same nature in any phase). I should mention this, you'll like it; this is the case where the shortcut rule \theta
symmetry= \frac {360}{J} breaks down (because it is undefined where it should be zero). The shortcut only works for J not equal to zero. So, for J = 0 the rule could be expressed as its inverse, \theta
symmetry= \frac {J}{360}, but what's the point of having a rule that works for only one situation. So I throw that one out at J = 0, and the usual shortcut works in every other case.
f1(1285) could be viewed as having its angular momentum and spin momentum vectors coupled in the same direction and rotating together. The combined vector rotates about the axis only once every phase, hence J = 1. Simple enough to visualize.
f2(1270) could be viewed as having angular momentum and spin momentum vectors that are rotating in opposite directions about the axis. Twice in every phase, the vectors will be opposite to each other, and twice in every phase they will coincide, hence J = 2. The particle will "look" the same twice in each phase, hence a symmetry angle of 180 degrees.
Now that I've nailed out those examples properly, I will try to think about the other things you have said and reply. I can see how you can make a spin-2 system classically out of two vector objects, like if you had a mechanical system that performed this, for example. I'll try edit this post again as soon as I can, and I hope I did the symbols properly; if not, then you will know how truly computer-illiterate I am...