Recent content by 0mega

http://cyberleninka.ru/article/n/o-vliyanii-uskoreniya-na-pryamolineynoe-dvizhenie-zhyostkogo-sterzhnya-2-rassinhronizatsiya-chasov Formula (29)

I am surprised that You agreed. :rolleyes: Usually begin to argue. Yes. The standard definition of simultaneity leads to a curvature of space. Geometry IMHO is a conditional concept.

IMHO space is flat. While I do not want to say more. I think Demistifier support.

I would add to Your list yet geometry in non-inertial frame of reference. Very curious. Whom do you mean? Maybe You give a link?

You mean paper of Franklin? Equation (5) in section 2 strictly speaking incorrect, even though the correct output - a cable is break.The distance between the 2 ships, depending on the time in Bell's paradox is the formula (3) post 325. In section (3) all right. In conclusion, I do not...

Let me explain one more thing. When rigid accelerated motion of the rod all its points move differently. Front point - at a slower speed than the back. Therefore, the region adjacent to the front end of the rod is reduced less than the back. This leads to differ from the Lorentz formula. Right...

You are looking at 2 spaceships, which are not hard core. Before solving the task of Bell's we have to consider rigid rod. If the rod is rigid in non-inertial reference frame associated with the back point, then in the laboratory frame of reference he will be nonrigid. The concept of rigidity is...

The correct formula for the contraction of Lorentz in the symbols of Franklin is d=\frac{\sqrt{1+2a'(1-v^2)d'+a'^2(1-v^2)d'^2}-1}{a'\sqrt{1-v^2}} She also has long been known

Yes. The correct math is based on the transformation Moller

I will continue a little further. Speed anterior point on the back gives the derivative (3), i.e. u=\frac{dx}{dt} (4) u=\frac{W^2L^2shWtchWt}{\sqrt{1+W^2L^2sh^2Wt}}+WL shWt By the time the t to back clock on the front will take time (5) \tau=\int{\sqrt{(1+Wx)^2-u^2}}dt If we substitute here...

Moderator sent me a message: "Making references to other forums are not considered as valid references. Please re-read the PF Rules that you had agreed to". :eek: Ok. If it violates the rules, I am ready to you to explain the incomprehensible. I repeat that this problem has long been solved...

For clocks in rectilinearly moving frame of reference value unsynchronization does not depend on the law of motion frame of reference, but only to the magnitude of its velocity at a given time (formules (4.6), (4.9)).

Dear Matheinste. The solution of the problem of unsynchronization of clocks on a rest rod is in http://www.sciteclibrary.ru/rus/catalog/pages/9058.html