Recent content by 2h2o

I said it can't be solved explicitly, that's who. I am also an idiot for not seeing that even when it is, retrospectively, so obvious. So thank you for pointing that out. No wonder I was running in circles. Cheers!

You're given everything you need for the equation, except for the "soft" values Reynolds numbers that are a result of laminar flow. Most agree on the following: for circular pipe flow only laminar: Re < 2000 transitional: 2000 < Re < 4000 turbulent: Re > 4000 So, pick a Re that you think will...

No, the integral itself isn't the problem. My problem was the V term inside the integral, which comes from the virial equation of state (not the ideal EOS). The V-based virial EOS I was working cannot be solved explicitly for V and therefore cannot be meaningfully substituted into the integral...

Does the solution seem reasonable? How could you check? Here's a hint. :-)

You should always start with intuition. Would the plank be floating if its density were equal to that of water? Does styrofoam float on water? Is it more or less dense than water?

I think I may understand where you are confused. You can calculate how much mass is displaced, but you need to consider the full geometry of the board to find its average density.

Ok. Going further. Gave up on iterative solutions. Now trying to derive fugacity now in terms of dV. ## f = P*exp[ (G - G^*) / (RT) ] ##and recognizing ##(G - G^*)## as a departure function: $$(G - G^*) = [H - H^*] - T[S - S^*]$$ ##H^* = 0, Sd = - (BR) / (PV)## (using the virial EOS) and get...

Homework Statement Find the fugacity from the virial equation of state, where B is a constant. Homework Equations Z=\frac{PV}{RT}=1+\frac{B}{V} Don't know how to do underbars in TeX, but the V terms are on a per-mol basis. B is a constant and no further expansions of the EOS...

Ok, thanks for your help. Sounds like the problem was in the method of data acquisition. Unfortunately the instructions that I had available were not very clear about the technique of how to use the device. "The field from a bar magnet is a 3D pattern, spreading out from the N pole in every...

It is a "Magnetic Field Sensor." (link below) I found a product page for it. It uses the Hall effect to measure the radial and/or axial component(s) of B. http://www.pasco.com/prodCatalog/CI/CI-6520_magnetic-field-sensor/ I still don't understand why I didn't obtain any signed values, but...

In order to solve these problems, you need data about any three of the four variables (P, V, n, T) Your example only specifies two (P, V). Without a third specification, it's impossible to know if one or both mass and temperature have changed. I'd like to say "typically" ideal gas problems...

q would only = 0 if the two particles were coincident. But to hopefully get you pointed in the right direction: the electric field of a dipole is not zero (except in the limit as r-->infinity.) Moreover, electric fields of point charges superimpose, just as forces do. So the pointcharge...

These are non-moving point charges. There are a couple of other relationships that I might try to use to examine this scenario. One is the electric field of a point charge. The other is the forces between two charged particles separated by a distance r. Try it. :-)

q in this case is the fundamental unit of charge. Both the electron and proton have the same magnitude of charge, but opposite. Since you're dealing with a single electron and proton, q is just 1.60E-19 Coulombs; sign depending on which particle you're examining.

A direction vector is exactly that: it signifies only direction. It says nothing about position or magnitude; hence it may be on the line, but not necessarily. But that's not terribly useful, just in of itself; so your textbook is probably just going to use it as a way to build up to...