Recent content by 2nafish117

i solved it just a few minutes back! my solution is in page 1

your solution takes the fundamental definition of current (i dint think of it) my solution has the assumption that the average current is proportional to the average velocity. your solution proves my assumption right! and to clarify t proportional to 1/V in your solution right?

let me try answering this question again the (average current) proportional to (average velocity)(charge that each carry) {the average velocity has a linear relation to the final velocity from post #18} we knoe that the final kinetic energy is equal to the work done on the spheres by...

intuition says t depends on V. and the current is also proportional to the charge on the spheres

since the initial velocity is zero and acceleration uniform v avg =v final/2 they are directly proportional!

i used integration(to find averages) and found that v avg =v initial +1/2*a*(t initial +t final) or else a = 2*(v avg - v inital)/(t initial +t final)

to clarify q proportional to V and is it that t proportionat to 1/V? from h = 1/2*(Eq/m)t^2

i think i made a mistake ,the velocities i considered weren't the average they were the final velocities. the average velocity will be the (distance bw plates)/(time taken to go that distance) since the field is constant in parallel plate capacitor, the acceleration is also constant. so...

but i have assumed that the current is proportional to the average velocity of the spheres.

just so you know the answer key given to us isn't final and is subject to change. but I am pretty sure the answer keys are right

how do you know that the sphere attains the same potential as the plate, it might fly off to the other plate well before it gets charged to the same potential. ok assuming that it does get charged to same potential then V(potential of sphere) = k*(charge on sphere)/(radius of sphere) . because...

yes but q is a constant. or does it also depend on V oh wait it does, as you increase V charge on the balls also increases. but how do i know the relation between them?

hello nascent oxygen it follows from the work energy theorem KE=1/2mv^2=work done on the ball but the work done on the ball=potential through which it is accelerated*charge on ball so 1/2mv^2=qV here V= potential v= velocity we see v^2 proportional to V

hello nascent oxygen it follows from the work energy theorem KE=1/2mv^2=work done on the ball but the work done on the ball=potential through which it is accelerated*charge on ball so 1/2mv^2=qV here V= potential v= velocity we see v^2 proportional to V

Homework Statement Homework EquationsThe Attempt at a Solution 1) the first question is easy,it is (C) because these charged balls are repelled from the similarly charged plates and accelerate towards the negatively charged plate,and once thy stick to the second plate they transfer double the...