Recent content by 404

  1. 4

    Lab based conservation of energy quesiton.

    Ok post #4 you implied PE wasn't just the weight like I originally said, so the only other option is both(sure as well can't just be the cart). Lol...sorry but you're not helping much... it's been a long day, tired, was justing looking for a quick answer. nvm, I'll just ask my teacher tomorrow.
  2. 4

    Lab based conservation of energy quesiton.

    Ok so only the cart is moving. So PE both and KE just cart mass? But I know that's wrong because then PE ends up around about 90 times bigger than KE. What is it then? will you please kindly just cut to the chase?
  3. 4

    Lab based conservation of energy quesiton.

    Well for the PE side I just used the mass of the weight for the KE side, I got both masses. I already did all the calculatiosn etc, just looking for some quick confirmation or where I went wrong.
  4. 4

    Lab based conservation of energy quesiton.

    Ok, there is a cart on a table(very little friction) with a string attached to it. The cart and the string goes over a pulley at the edge of the table, and has a weight hanging down the side of the table. So when you let go of the cart, it will accelerate until the cart hits the floor, then go...
  5. 4

    Where Did I Go Wrong in Calculating the Launch Speed of a Pinball?

    okay, thanks.
  6. 4

    Where Did I Go Wrong in Calculating the Launch Speed of a Pinball?

    Well how do you set it up then? I'm more confused then before I posted this now :( so is it PE(1) = KE(2) + PE(2)? where PE(1) = 0.5Kx^2?
  7. 4

    Where Did I Go Wrong in Calculating the Launch Speed of a Pinball?

    but if the initial KE is 0, how do I find the initial velocity that was suppose to be 1.63m/s?
  8. 4

    Where Did I Go Wrong in Calculating the Launch Speed of a Pinball?

    My work so far... KE(1) + 0.5(k)(x)^2 = Work (gravity) + PE(2) where 1 is the bottom of the incline plane and 2 is the top. and 0.05m is the distance between the 2 points. (using bottom of incline plane as reference point) I found the height at 0.05m up the incline to be 0.0087m and the x...
  9. 4

    How Do You Calculate the Instantaneous Power of a Car Engine?

    Car with mass of 1500kg, accelerates from 0 to 18 uniformly in 12 sec. Air drag is 400 N. Find the inst. Power output of engine at t = 12s. just before car stops accelerating... Well I found the average power to be 23850 w, but how would you get the instantaneous?
  10. 4

    Will the Projectile Hit the Falling Target?

    Oh I see now. Thanks
  11. 4

    Will the Projectile Hit the Falling Target?

    bump, does anyone know?
  12. 4

    Will the Projectile Hit the Falling Target?

    lol... thanks, I read it, but it doesn't seem to give an algebraic solution.
  13. 4

    Will the Projectile Hit the Falling Target?

    Yeah, I already know all the things talked about above from all the other projectile motion questions I did... I made some progress, but can someone please tell me what the answer would be? So atleast I would know if I solved it right or not...
  14. 4

    Will the Projectile Hit the Falling Target?

    no, the gun is below the target, but it is aimed straight at the target. Well, I suppose their time value would be the same as well.
  15. 4

    Will the Projectile Hit the Falling Target?

    A really tough question well.. for me atleast Any hints? I'm still trying to figure out where to start :cry: EDIT: *though = tough ...can someone please tell me what the answer would be? So atleast I would know if I solved it right or not.