OK...think I have muddled through
Force = CoF Static )Ff-s x N
Force = 0.145 x (100 x 9.8m/sec sq)
Force = 142.1
F=ma
142.1 = 1000kg x a
0.1421m/sec sq = a
Vf sq = Vi sq =2ad
(0m/sec) sq = (29.3m/sec)sq + 2ad
-858.49 = 2(.1421)2d
-858.49 / .2842 = 2d
3020.73/2 = d
1510.36 m =...
Man...have I spent too much time in financial spread sheets today
OK...
Static CoF (Ff-s) = M x a
Ff-s = 0.145 x 9.8m/sec squared = 1.421 m/sec sqrd
1.421 m/sec sqrd = 1000kg x a
1.421 m/sec sqrd / 1000kg = a
0.001421 m kg/sec sqrd = a
Vf sqrd = Vi sqrd + 2ad
(0 m/s) sqrd = (29.3 m/s) sqrd =...
OK...synapse lapse again...
I have Velocity initial (Vi) = 29.3m/s and Velocity final (Vf)= 0ms/
Calculated Ff Static = 1.421 (m/sec sq?)
Calculated Ff Kinetic = 0.9947(m/sec sq?)
Where do I go from here to find the distance?
1. Need help with daughters physics...been 35 yrs since I was in class.
100kg car moves at speed of 29.3m/s on horizontal road
Static CoF = 0.145
Kinetic CoF = 0.1015
Acceleration of gravity = 9.8m/s squared
Road is wet
Neglect Reaction time of driver
What is shortest possible stopping...