Recent content by _physics_noob_

Okay so I took the tanarc(-33.32/350) and got -5 degrees... Then I added 360 to get 355 degrees... So I would add 180 degrees instead of 355 because 355 degrees would be the angle it penetrates the ground? and 175 degrees would be the angle at which the projectile hit the ground?

So instead of adding 360 degrees, I should have added 180 degrees?

So the timing is incorrect? This is what I did... y=(350m/sin(0))t-0.5gt^2 -55m=-0.5(9.8m/s^2)t^2 -55m/-4.9m/s^2=t^2 t=3.35s so I rounded it to 3.4s

Homework Statement A projectile is fired horizontally from a gun that is 55.0 m above flat ground, emerging from the gun with a speed of 350 m/s. a) How long does the projectile remain in the air? b) At what horizontal distance from the firing point does it strike the ground? c) What is...

Okay cool and I figured, that's how it is my book but for some reason my professor uses v1 and v2

Thanks @rikardus ! How did you come up with that expression? did you made Δx = (v1)t+1/2(a)t^2

So if v1=0 then i could use x=v1t+1/2at^2... 0.176=1/2(-9.8m/s^20)t^2 then solve for t^2 t^2=0.176m/(-4.9m/s^2) but it wouldn't work because I can't square a negative or do i have to use the positive 4.9m/s^2

Homework Statement A meter stick is held vertically above your hand, with the lower end between your thumb and first finger. On seeing the meter stick released, you grab it with these two fingers. You can calculate your reaction time from the distance the meter stick falls, read directly from...