Recent content by _VexatioN

"y just has to be in the 2nd position in the first set, and 1st position in the second set" and this has to be true for EVERY set in the function; or ANY set in the function?

A) So as long as any elements {x,y,z} in the set follows the pattern (x,y) , (y,z), (x, z) the set is transitive? The reason I thought it wasn't transitive is that there's nothing linking (2,2), (3,3), or (4,4) to each other.

A) Even though it doesn't apply to the whole set? K) >Not proven to be false. > Therefore true. You have to be joking me with the logic for those two! Thanks so much for the help, as you may have noticed I would have been screwed if you haven't have helped me with those. Dave C., Coffee on me...

Sorry, I probably should have just marked the ones I ticked.

Suppose that R1={(2,2),(2,3),(2,4),(3,2),(3,3),(3,4)}, R2={(1,1),(1,2),(2,1),(2,2),(3,3),(4,4)}, R3={(2,4),(4,2)} , R4={(1,2),(2,3),(3,4)}, R5={(1,1),(2,2),(3,3),(4,4)}, R6={(1,3),(1,4),(2,3),(2,4),(3,1),(3,4)}, Determine which of these statements are correct. Check ALL correct answers...

I got Q2 eventually; I also got Q5 but Q's 3 and 4 are beyond me. Question 3 goes right over my head, I keep getting Question 4 wrong and no clue why. Question 4: (1 pt) Determine which of these relations are reflexive. The variables x, y, x', y' represent integers. A. x∼y if and only if x+y...

If it makes you feel any better I'm stuck on question 2.