Recent content by a1call

Thanks very much again for the reply and the referenced article. It is very similar to the experiment in OP, except that instead of the one-slit-blocked apparatus it uses 2 detectors to get the which slit info for the both-slit-unblocked apparatus. Because of this no interference fringes are...

Thank you for the reply Dr, Actually I am not quite sure what you mean. Am I correct to conclude that I was wrong to assume that if single/multiple half/halves of entangled particles are observed to behave as particle (or wave) then the other entangled half/halves will (have to) be observed to...

Thanks for the reply. I will see if I can dig out info on Ballentine problem 9.6. FWIW (my bold): Thanks again Peter.

Well, not lately, but I have researched the subject in the past and watched lectures from Feynman. There are experiment which I don't understand such as quantum eraser. So either I have not came upon the exact experiment that I am asking about or I have not understood it, hence this thread.

Hello all, I hope that all is well. I was chatting with the Copilot app abut the quantum effects and according to it, the following exact experiment may not have ever been conducted. The question is: What happens if entangled photons are created and each half is sent through 2 different double...

Nice find. It appears the slinky is overstretched compared to 1 g, making the delay over-shortened. Also the far end never gets stable. Perhaps the free fall duration is too short for the proper conduction of this experiment. Perhaps someone will try it aboard the International Space Station at...

Got it. Thank you.

Yes I understand now, with the leverage playing a role. Correct?

To be more precise the COM would be on the slinky axis point closest to the wire-midpoint, but I think that is inconsequential to the argument. It seems my problem arose from the false assumption that the COM would have to react instantaneously to a release and without delay. But as shown in...

I can't see why not. If you froze the slinky stiff with one half composed along a straight line and the other half uncompressed but straight along the same line, the wire midpoint would be the balancing point. To make sure we are talking about the same thing by wire-midpoint I am referring to...

Thank you for that. In the slow motion there is a delay in the wire midpoint reacting to the release, which would falsify my argument that the COM would have to react immediately to the release. So, is the angular momentum preserved briefly in the spinning scenario?

I would think yes if the compression is linear and along a straight line (which may not be the case here). In a linear compression, the two halves of the slinky's mass will be on the opposing sides of the wire midpoint. If the compression is not along a straight line however, the COM can be...

I actually do have a Slinky at hand, but do not have the means to record or room to spin it. I can visually observe the "levitation" in the drop scenario. I also tried a partially spin scenario and the far end did seem to move away immediately, but the test was far unreliable for a definite...

The only alternative I can think of is that the near end goes into such crooked formations that would shift the COM away from the wire midpoint and in such form to maintain the angular momentum of the far end briefly. So I just don't know.

That is a good question. Not 100% sure. But assuming that the COM starts on a straight path immediately after release, then relative (classically speaking) to the COM before the contraction reaches and surpasses the COM (at slinky's wire midpoint irrelevant of the spring length ), the COM will...