Yes , this is what i meant (or I think the question meant).
I already know (from working with some numbers) the Pn = 0.28 = 2/7 (more or less)
But the problem is that I need to make a general formule / Function that will compute that
I copied the Question from the sheet I'm trying to solve so That's the way i understood what to do :
for any number "m" I need to find the the entire field of possible answer without surpesing it (thus p(m)!=0) , so let's say I want to get to m=3 .
then
p(3) = 1*(1/6) + 2*(1/6^2) +...
Nope , It can be endless number of rolls but using same dice all over again.
So let's say that p(1) = 1/6 as there is only 1 way to get it , by getting 1 in the first roll.
then
P(2) = 1/6 + 1/36 as u got 2 options now , either u get 2 in first roll or 2 times one with 2 rolls.
and...
I ran into this next problem and I am having hard time getting a final answer for it for every m :
A dice is rolled and summed over and over , What is the probability That the sum will be "m" , "m" is a positive integer
My problem starts after the numer 6 , as I start to loose options...