Recent content by adam199

I solved it by using the apparent weights as the normal reactions at each point and using that to find the velocities and accelerations needed to solve the problem.

Here's a picture: Edit: Here's a description of the problem in case the picture isn't clear. A 54-kg pilot flies a jet trainer in a half vertical loop of 1200-m radius so that the speed of the trainer decreases at a constant rate. Knowing that the pilot’s apparent weights at Points A and C...

Actually, the formula comes out to 200a^2-400a+3200-4By=0, I made an error adding up the a^2's. Still stumped on how to determine the value for a that would bring a minimum reaction at B. I tried manipulating the force and moment equations together to come up with a, but there's something I'm...

Sure. Ma equals the moment of area cross the area for each triangle (at point A). So, for the first triangle on the left side, I got an area of .5(1800)a=900a (area of a triangle), and x-distance of the centroid of the triangle, which is 1/3 the height of the triangle, or a/3 in terms of...

Picture of the problem: Relevant equations are the ones used to find the reactions at the supports (moment about points, forces in the x and y) and the ones used to determine the centroid. I'm having a hard time finding a. I found the moment of area for each triangle, with the origin at A...

Nevermind, I found the solution.

A conducting spherical shell of radius 11.0 cm is charged to a potential of 5.00*10^4 V. What is the value of the electrostatic potential 5.0 cm outside the surface of the sphere? V=(1/[4*pi*(epsilon naught)])*(Q/r) <-- outside of the shell V=(1/[4*pi*(epsilon naught)])*(3Q/2R) <-- inside...

thanks

I tried using w=a-tb. I dotted both sides by b, and got 0=(a-tb).b, where t is the only unknown, but I got stuck again. I'm not quite sure how to solve for t at that point.

Consider the vectors a=<2,4,-3> and b=<4,-5,6>. Determine vectors v and w such that a=v+w and v is parallel to b while w is orthogonal to b.The dot product of two orthogonal vectors is zero and the cross product of two parallel vectors is zero. A parallel vector is a multiple of the chosen...

Homework Statement A horseback rider is pulling a log behind him attached via a rope. The force of tension along the rope is 2000 N. What are the vector components of this force given the length components of the rope? The length components are x=1.5m y=2m z=2m. This problem is 3D so there are...

Never mind. I eventually figured out how to translate the upper and lower limits of the integrand over to the final versions. Thanks.

I substituted sin(t)=x and got: 1/sqrt(1+x^2)dx but when I use the trig. substitution with this integral, I come up with the same thing I had before. I don't think I understand how to do it substituting sin(t)=x and then using a trig. substitution, like Mark said.

The integral from 0 to pi/2 of: cos(t)/sqrt(1+sin^2(t)) dt I'm supposed to use trig. substitution to find the solution. I started by using the formula a^2+x^2 to get x=atanx. In this case, sin(t)=(1)tan(θ), and so cos(t)dt=sec^2(θ)dθ and so I substituted this into the equation and got...

I know this is late, but I wanted to thank you for helping me clear things up.