Recent content by AdanSpirus

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    Physical Pendulum Question for Moment of Inertia

    Uhhmmmm so is that what I said? I = (1/12)ML^2 + M(L+R)^2? Because the parallel axis theorem is the following equation:I = Icm + Md^2
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    Physical Pendulum Question for Moment of Inertia

    I still don't understand >.< Since the Parallel Axis Theorem states that its I = I(center of mass) + Md^2, so wouldn't my statement be correct? I = (1/12)ml^2 + M(L+R)^2?
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    Physical Pendulum Question for Moment of Inertia

    So is the moment of Inertia then I = 1/12ml^2 + M(R+l)^2 ?
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    How Do You Calculate the Moment of Inertia for a Compound Physical Pendulum?

    1. Homework Statement Ok So here's my question. The physical Pendulum consists of a thin rod of mass m = 100 g and length 80 cm, and a spherical bob of mass M = 500 g and radius R = 25 cm. There a pivot P at the top of the rod. (Sorry, I don't have a picture >.<) a) It asks for the center of...
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    Physical Pendulum Question for Moment of Inertia

    Homework Statement Ok So here's my question. The physical Pendulum consists of a thin rod of mass m = 100 g and length 80 cm, and a spherical bob of mass M = 500 g and radius R = 25 cm. There a pivot P at the top of the rod. (Sorry, I don't have a picture >.<) a) It asks for the center of...
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