Homework Statement
There is a flag mounted at the top of a building. The angle of elevation from a point 200 ft. to the flagpole's base is 70°, and the angle of elevation from the same point to the top of the flagpole is 82°, find the height of the flagpole.
Homework Equations
Law of...
Thanks for the feedback guys!
My guidance counselor mentioned some of the same things. I was thinking about maybe splitting up cyber school with public school. I would attend public school for my sciences classes because I definitely want to have hands on experience with labs...
I will be entering my senior year next year, and I am pretty determined I would like to pursue a career in sciences, which field exactly I still am undecided.
Anyhow, I have a 4.4 GPA in my public school. I tend to miss a lot of days in school...lately I've been realizing how inefficient it...
"The static friction can be discarded when solving for work since static friction moves over a negligible distance."
Is this now correct statement now?
I do not understand. In my scenario, I am attempting to calculate work. I am dealing strictly with distance. It definitely creates a resisting force. Is that not irrelevant when dealing with work, though, since distance would equal 0?
From what I have researched they do not. The static friction can be discarded since static friction moves over a negligible distance. Here's my new attempt to solve for the work done on the boxes as they are pulled 5m.
There are two forces acting upon the boxes. The rope and friction...
If 26.88m/s is the vertical vector and I find initial horizontal velocity velocity (10.34m/s) and use Pythagorean theorem I come up with the same answer I got before...28.8m/s. Does this seem to be the correct velocity of the rock right before it hits the ground?
Homework Statement
There are three boxes stacked on top of each other. Each of the boxes has a mass of 250 kg. There is a chord attached to the bottom box applying a force of 7,000N. The coefficient of static and kinetic friction are: μs = .950 and μk = .900. What is the work net if the boxes...
Okay, on another note: If there rock were to hit the ground at a velocity of 25m/s, what would be the heat loss.
To attack this problem, I'd find initial kinetic and initial potential and add them to get initial mechanical energy.
Initial:
K = .5(m)(v)^2
= .5(1kg)(13.5m/s)^2
= 91.125 J...
Energy Lost to Heat ~ Spring (Solved)
Homework Statement
--->What is the energy lost to heat?<---
spring mass = 15g = .015kg
spring constant = 220 J/m^2
spring is compressed 5cm (.05m) then released to achieve maximum height of 102 cm (1.02 m)
Homework Equations
U = .5(k)(x)^2...
Here is new NEW attempt to solve the problem using Conservation of Energy.
The initial Velocity in the y direction is:
Vy = 13.5m/s*sin(40°)
Vy = 8.7 m/s
Energy (E) = Kinetic Energy (K) + Potential Energy (U)
The initial Kinetic Energy (Ki) is as follows:
Ki = .5(m)(v^2)
=...