I did not apply Coulomb law immediately after the stop. I compared the electric fields on a charge before and after stop relative to 2 observers. I found that Lienard Wichert potential before the stop relative to the platform observer is larger than Coulomb potential after the stop. For the...
Fine.
So how if the 2 ends are programmed to start moving at the same acceleration rate? Similarly to Bell`s spaceship paradox, there should be a tension on the string because its length now is larger than the contracted length. So How did this contraction come from?
So we are facing 2...
So would you please explain how the platform observer can see the length of the train that goes from 6250 feet before moving to 5000 feet after moving without seeing the rear end starts moving before the near end?
This is clear for me thanks. I was wondering in my previous query why a lateral force that ghwellsjr suggested for the platform observer is equivalent to the compression force relative to the train observer even if we have prior information that the initial length of the string is 5000 feet not...
While you are holding the rubber to a stretched length, you approach it near a heat source so as it chemically looses its elasticity even it is maintained at the same length.
I did a sketch of a solution. I compared the Lienard Wichert potential created by a moving charge on the one following it in the same direction of the motion. And I compared it with Coulomb potential after the 2 charges come to a rest.
The result is the potential during the motion relative to...
The rubber band is an example of the train. The stretch on the band when holding between hands resembles the strain imposed on the train when the 2 ends maintain its rest length even during the motion and hindering it from reducing to a contracted length. The sudden release of the elasticity...
Then in order for the length contraction to happen from the beginning, both ends should be in different states of motion relative to a platform observer. And in order for the train to regain its original length after coming to a stop, both ends should end in different states of motion too...
So how length contraction occurs in the beginning of the motion? To my understanding from this thread, the rear end of the train should start moving before the near end relative to the platform observer which leads to a contracted length. So for that observer, 2 ends have different states of...
That stain is due to a force that prevents the train to go to a contracted length relative to the platform observer right? So it should be felt during the motion and an opposite force would be felt if such strain had to be relieved and the length would be allowed to go to a contracted length...
But how do we know that the original length at the start of the motion was 6250 feet? Is that possible that the train would start moving with both ends accelerating simultaneously? If so, the train length would remain unaltered before the motion, during the motion and after the stop as long as...
If both ends come to a simultaneous stop relative to the platform, then the distance between them should not altered before and after the stop. That may only happen when the rear end stops before the near end which is not my scenario.
Now consider, a train carries the 2 charges where one of them is attached to its near end and the other one is attached to the rear end. Again consider that the train comes to a sudden stop relative to a platform observer so as both near and rear ends stops immediately at the same time. As it...
The same would also apply if our scenario consists of 2 magnets moving one ahead of the other in one direction. B x= B`x , and there would be no change of the force between them in both frames! So if you agree on the 2 scenarios I would take you to more important result.
But my example considers 2 charges moving one ahead of the other not in parallel. And according to the transformation of electromagnetic field, the electric field in the direction of the motion does not change, so does the force between them in this direction. Ex= E`x & Also B x= B`x ...