Recent content by AdrianGriff

Well the "goal" is to attempt charging a 3.7V 350mAh battery with a turbine with a blade diameter of approx. 12mm. Obviously this is very small, so I'm curious if creating a teeny tiny generator would be viable.

I am referring to wind turbines with relatively lower speeds on a much smaller scale. And I am familiar with induction motors/generators and the like, but I am curious as to if there are any differences or more efficient methods for a generator in a wind turbine that can be used on small scales.

I understand that the turbine drives rotational motion of a low and high speed shaft which rotates within the generator, but how exactly, and with what components/materials does this create electrical energy? Is there a minimum required rotational speed or torque required to generate...

Yes I standardized all units haha

I noticed that your units for ##ξ## were not ##ft^2/s^2## are they not supposed to be that way? From the equation for ##ξ## I see no reason why both units distance and time should not be squared. Also, when you did the 'sanity check' you said Escape energy = 1/2mv^2 and that you got an energy...

It is not intending that 100 nmi is lower than the entry altitude, it is asking what the velocity and flight-path angle were previously when higher in orbit assuming it is on an entry path back to Earth.

Well, my first instinct to attack this problem is to find both the Specific Mechanical Energy ##ξ## and Specific Angular Momentum ##h##. I did this using the velocity ##v = 25,000 ft/s## and ##r_{entry} = 300,000ft + 20,902,230ft = 21,202,230 ft##. $$ξ = \frac {v^2} {2} - \frac {μ} {r}$$ Where...

I essentially found the specific angular momentum of the vehicle when it enters the atmosphere (ie 300,000), so h = rv*cos(flight-path angle), and then equated that to h at the altitude of 100 n mi. Since I need both the veocity and flight path angle at the altitude of 100nmi, I solved for the...

Would a photo do the trick?

A space vehicle enters the sensible atmosphere of the Earth (300,000 ft) with a velocity of 25,000 ft/sec at a flight-path angle of -60 degrees. What is its velocity and flight-path angle at an altitude of 100 nautical miles during descent? (Assuming no drag or perturbations, two body orbital...

Oh, okay. Thank you :)

Does treating ##\mu## like a function, and using the chain rule also create the same output? As G, M, and m are all constants and would all derive to be equal to zero? Or must it remain solely as a parameter? Thank you a lot though :)

Thank you :) However the only ambiguity I can feel for here is that is ##\mu## not a function? If ##\mu = G(M+m)## is that not considered a function during derivation?

Could you invest a bit of time into helping me understand this question? I don't mean to ask too much, but this is a pestering and burning question. Perhaps it is too out of my grasp (I am only 18, still in high school), but regardless, I would like to know why it is the way it is. I could send...

Well this is only a small step in deriving the conservation of mechanical/orbital energy, ##ξ## provided in The Fundamentals of Astrodynamics by Roger R. Bate, But the only extra information that I can think that would be important is that: 1) The orbit is perfectly circular 2) There is no...