Recent content by agreaves

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yeah, sussed it, 3x - 2x does not equal -x thanks for the help

my working was pretty much the same as the others, just swapping the (1-x)'s and x's around 1/3 = [5*10x/(10x+5)] / [(5*10x/(10x+5) + 10(1-x)] got this to 1/3 = [50x]/ [5*10x + 10(1-x)(10x+5)] then to 1/3 = [x]/[-2x2+2x+1] divided through by 50

also, wouldn't it work if the slider was at the bottom, which would put the resistors in series, as 5/(5+10) is still a third which is what we want

Hi, I've just tried this method and couldn't get it to work, can you show me this other method, when i tried i canceled it down to 2x2 -x -1 =0 not sure where I made my mistake, I got the other way to work fine, can't see why it didn't work swapping them round