Recent content by Ajay N

max=-kx+F or m d2x/dt2=-kx+F may=-ky or m d2y/dt2=-ky

Fy=-ky Fx=-kx+F

Then there would be no change in the the time period since F is a constant.

The net force acting on the particle at (x,y) is k√(x2+y2) . F=k√(x2+y2) The component of this force along x-axis is Fx Fx=k√(x2+y2) * x/√(x2+y2)=kx. From this we can infer that the x coordinate is oscillating. Amplitude is x0. At t=0 x=x0 therefore x=x0cos(ωt). Similarly we can derive y0cos(ωt).

In that case x=x0cos(ωt) and y=y0cos(ωt).

I tried deriving the equation but with no success. I am a high school student. Can the equation of motion be derived with my limited mathematical knowledge ? But this problem is from a high school physics olympiad book.

Can I take the system as two independent oscillators oscillating along x and y-axis ? By this method the oscillation along the y-axis is completely unaffected by the external force. The force along the x-axis being a constant doesn't affect the time period of the oscillation along x axis. From...

Well I don't think I know how to transform the coordinates. I might have to look into that.

My first impression was that since the external force was constant it wouldn't make any change on the period of oscillation of the system. But on further thinking I found that if I were to only consider the one dimensional oscillation of the particle then the component of force along the string...