I assume you mean to solve the equation for Dy and substitute that back into the other equation. But when I solve it for Dy I get:
Dy = -Dx - 3x - 3y +2 Which is all fine and good except for the -3y. Which poses a problem when substituted back into the first equation.
The problem with this is that, the part I BOLDED is actually (D+3) in the original equation. However that may be on the right track. I tried multiplying the top by (D+3) and the bottom by D.
I then added the equations and come up with this:
D2x(D+3) + D(D+3)x = 2D + 3t + tD
Simplified...
If I do that then I get D2x + Dx + 3x - t + 3y = 2
Then I don't know how to deal with the -t + 3y
Thanks for the idea though. I hadn't thought of it.
Edit: After another look you could then write it as D2x + Dx + 3x = t - 3y + 2
But I still don't know what to do with it from here. I can...
Hi Guys,
I'm tying to solve a system of equations. I know I need to operate on the top and the bottom both in order to isolate the X's and Y's, but I can't seem to figure what to operate on them with. Here are the equations, any help is appreciated. Thanks
D2x - Dy=t
(D+3)x + (D+3)y=2
I...