Recent content by Akaramos45

Could i say that the increase in energy due to an increase in pressure is neglible?

is there anything i can assume in order to make this true?

That's true. but this question allows me to state assumptions

I was thinking since we can assume that all of the energy of the hot gas is transferred to the steel. Wouldn't what you said before still work?

Excuse me, Mr.Haruspex it's getting quite late for me could you please show me what you mean?.

I am so confused. Could you please give show me how it meant to be done?

I think this is way it should be done. I see that you are offline. Thank you very much for you help. This might be wrong, but it's too late now the homework is due tomorrow. If there is any mistakes with please just list them so i can take care of it late

(0.313)(448)(Tf - 18) = 59.5 J Tf - 291.15 = 59.5/(0.313*448) Tf = 291.57 K Therefore there is an increase of 0.42 degrees

Density of steel = π(0.011)^2 - π(0.01)^2 * 0.6 = 3.96 x10(-5) * 7900 = 0.313 Kg

Do you mean to use the internal energy that was calculated in part b?

I do not know the mass of air, or it's specific heat. So would it be correct if i said the energy. Also I do not know what to do from here.

The energy lost by the gas + the energy gained by the steel cylinder = 0 Since the energy is conserved. The mass of the steel cylinder = Volume x density = (π(0.01)^2 - π(0.009)^2)*0.6 = 3.58 x 10 (-5)* 7900 = 0.283 Kg MsCs(Tf - 18) + MgCg(Tf- 18) = 0

I am looking up specific heat

the volume of the steel?

I see. How do I calculate the increase in temperature of the steel. What formulas would I use?. I am sorry this is my first doing this sort of problem. Could you show me an example?