I know in Hollywood people fall a couple stories and grab onto a pole or something and survive, which most of the time doesn't seem too far fetched. But what if you were falling at terminal velocity and grabbed onto a horizontal pole? (The pole being a cantilever, and not flexible or anything at...
Homework Statement
Air is heated from 300 to 350K at constant volume, Find 1Q2.
Homework Equations
1Q2 = m(u2-u1)+1W2
u2-u1 = cv(t2-t1)
The Attempt at a Solution
The PV diagram of the process is straight up, so the area under the curve is 0, so the work done is zero.
Cv is .717...
Oh, thank you so much.
I took the moment about D, and set the two remaining forces equal to zero. Sum of Moments about point D = r x Fb + r x Fa = 0, would that be right? Then I just gather the i, j, and k terms and set them each equal to 0, and have a total of 6 equation (3 from the sum of...
B? That's what he expects the answer to be in, but I have never handled a problem in that manner so I don't know how to modify the equation. Unless that is stating that it only has a force normal (N) opposite to that of the wall, so all I would need would be Bx (N = Bx) and not By and Bz?
If...
Ok, thanks.
I got three equations so far.
Sum of X = Tcd*.617+Ax+Bx = 0
Sum of Y = -Tcd*.154+Ay+By = 0
Sum of Z = -Tcd*.77+Az+Bz = 2450
7 unknowns and 3 equations. Not looking too good so far.
So, I was thinking I should take the moment about point A since that would reduce 3 unknowns, but I...
Homework Statement
In the attachment
Homework Equations
Sum of the forces in the X, Y, and Z
Sum of the Moments in the X, Y, and Z.
The Attempt at a Solution
I don't believe I need help solving the problem, I just need help setting it up.
I can find the vector of CD, which...
The tension in AC = BC? Do you mean the tension in BC = DC?
I still don't see how the equation was formed, could someone explain how the equation was determined?
http://img10.imageshack.us/img10/8880/capturejfu.jpg
I did arctan(12/5) to get the degrees + 180 to get the angle from the X axis to B, then I just split the angles into components.
I did 100*cos(246) + 100*cos(theta) = 0, and I got 67 degrees.
Then I was doing the Y components, and realized...