Recent content by albert12345

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    What is the correct solution for the maximum compression of the spring?

    I've tried the same formula I used when I started this topic on another assignment of the same type. It shows that the solution in the assignment was wrong! IDIOTS! We were right al along :D Thanks for your help guys!
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    What is the correct solution for the maximum compression of the spring?

    I calculated the velocity when the box has slided down the plane: v= 5,581963937m/s (The speed is just before the box hit's the spring Then I put in the velocity in the ecuation I wrote earlier, together with the spring constant and then I solved for x
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    What is the correct solution for the maximum compression of the spring?

    I just tried it! It's weird cause I got the same answer again :/ k1 = (1/2)mv^2 equals U2= (1/2)kx^2
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    What is the correct solution for the maximum compression of the spring?

    Ok! But I don't understand how I should calculate it :/
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    What is the correct solution for the maximum compression of the spring?

    I really don't think it's right. It's going to be the same since Ug2=the height + the compression of the spring.
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    What is the correct solution for the maximum compression of the spring?

    There is no pic. for the problem, but I get your point. Does it really make that big differernce? And We have never had such problems before, so i think the spring is aligned with the plane
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    What is the correct solution for the maximum compression of the spring?

    It's from an assignment. I really believe that the answer is wrong, but it has never happened before so...I must have done something wrong.
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    What is the correct solution for the maximum compression of the spring?

    I agree. I came up with the answer: x ≈ 0,203m The right answer is: 0,0144
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    What is the correct solution for the maximum compression of the spring?

    I've tried a few times on this problem but I can't get the right answer... A box with mass m=1,05 kg slides down a ramp with angle=42.39°. Kinetic friction μ=0,1646 between the ramp and the box. It starts from rest. g=9,806m/s². The box hit's a spring with: k=792 N/m after sliding the...
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    How Far Does a Car Travel to Reach 4.61 m/s with Non-Constant Acceleration?

    So I just plug in my values here and solve for s, or do i have to antiderivate first? v dv/ds =ks^n
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    How Far Does a Car Travel to Reach 4.61 m/s with Non-Constant Acceleration?

    So I just plug in my values here, or do i have to antiderivate first? v dv/ds =ks^n
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    How Far Does a Car Travel to Reach 4.61 m/s with Non-Constant Acceleration?

    adx = adv Where x is the distance "s" so I get this: (1/2)*(x^2) = v2^2 - V1^2 Where v2 is the final speed and v1 is the starting speed=0.. Am i right or wrong?
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    How Far Does a Car Travel to Reach 4.61 m/s with Non-Constant Acceleration?

    Homework Statement A car accelerates with the acceleration a(s)=k*s^n m/s^2 s= distance in m k = 5,8 n=0,7351 The car starts the acceleration from 0 m/s How far has the car traveled when it reaches the speed 4,61m/s? The Attempt at a Solution When i anti derivate one time i will get...
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    What is the velocity of a car accelerating at a non-constant rate?

    The answer should be 4,0m/s. I got 8m/s when I integrated 1 time. What did i do wrong?
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    What is the velocity of a car accelerating at a non-constant rate?

    Im sorry! I wrote the expression wrong, it should be: A(s)=k*s^n m/s^2
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