i got it....after requesting the answer. your analysis was incorrect.
dsinθ=mλ is a maximum where m=1,2,3...etc <----- watch for this
dsinθ=(1+1/2)λ is a minimum where m=0,1,2,3...etc
Don't make my mistakes.
Replier: don't listen to him he's wrong.
That is the condition for single slit light diffraction where dsinθ=mλ is a local minimum. This is double slit diffraction. where maximum locations are dsinθ=mλ where m=0,1,2,3...etc
minimum locations are dsinθ=(m+1/2) where m=0,1,2,3...etc
yea I've gotten closer.
d=0.3mm (millimeter)
oh and i was being stupid about m values
since m starts at m=0 its max at m=1 and min at m=3
now i tried dsinθ=(3+1/2)λ1 where λ1=d/8
then sub in for dsinθ=λ2
thus I get (3.5/8)d=λ2
which gives 0.13125mm but that's not right either.
Homework Statement
A laser with wavelength d/8 is shining light on a double slit with slit separation 0.300 . This results in an interference pattern on a screen a distance L away from the slits. We wish to shine a second laser, with a different wavelength, through the same slits.
What is the...