Recent content by Alchemist90

i got it....after requesting the answer. your analysis was incorrect. dsinθ=mλ is a maximum where m=1,2,3...etc <----- watch for this dsinθ=(1+1/2)λ is a minimum where m=0,1,2,3...etc Don't make my mistakes. Replier: don't listen to him he's wrong.

That is the condition for single slit light diffraction where dsinθ=mλ is a local minimum. This is double slit diffraction. where maximum locations are dsinθ=mλ where m=0,1,2,3...etc minimum locations are dsinθ=(m+1/2) where m=0,1,2,3...etc

yea I've gotten closer. d=0.3mm (millimeter) oh and i was being stupid about m values since m starts at m=0 its max at m=1 and min at m=3 now i tried dsinθ=(3+1/2)λ1 where λ1=d/8 then sub in for dsinθ=λ2 thus I get (3.5/8)d=λ2 which gives 0.13125mm but that's not right either.

Homework Statement A laser with wavelength d/8 is shining light on a double slit with slit separation 0.300 . This results in an interference pattern on a screen a distance L away from the slits. We wish to shine a second laser, with a different wavelength, through the same slits. What is the...