Recent content by alemon

Could you... You first need to find the Spring Constant: K=f/x=200/5=40 So your spring constant (k) is 40, your displacement (x) is the 5cm. Now, first find your potential energy without the extra 200 grams added… u=1/2kx^2=1/2(40)5^2= 500 Now, find your second potential energy...

Maybe, I did this wrong, but... I doubled up the two 200s... Then I took the spring constant: K=400/5 K=20 Then I used the potential energy formula: U=1/2(20)(5)^2 and I came up with 250 Which is probably ALL wrong.

New member here... I have the following homework problem: "A 200-g mass attached to the end of a spring causes it to stretch 5.0 cm. If another 200-gmass is added to the spring, the potential energy of the spring will be" I know the answer is 4 times as much but I am not quite sure how...