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You have a unit vector right? and you need a vector in the same direction as this and of length 4?
Since the unit vector has length 1, all you need to do is multiply the unit vector by 4! Its as simple as that.
unit vector= ai + bj + ck
root of( a^2 + b^2 + c^2) = 1
new vector= 4ai +...
just use the definitions
[FONT="Garamond"]just use the definition.
let K be from Span(S1 U S2)
then K = a1V1 + ... + anVn ... + b1U1 + ... + bmUm +...
where Vi's are from S1 and Ui's from S2 for some ai's and bi's from the field
now all you have to do is group all the Vi's and group all...
Would anybody solve this problem for me?
I've tried it for a long time, but don't seem to get the answer.
I don't think I can apply L'Hospital's rule because the numerator is not zero or indeterminate while the denominator goes to zero
lim x-> -inf ((1+ e^(1/x))/e^x)
ok, if I assume...
A basis is basically a minimal spanning set (which automatically has to be linearly independent). Any set that spans the space will have cardinality equal or greater than the basis. Of course there are concepts of finitely generated spaces (spaces that have a basis with finite cardinality R^n...