Hi. :) Correct.
You need to be careful:
The correct way to solve the problem would be (with your choice of coordinate system) to set these equations:
x axis: sum of all forces in x direction = m * a_x
y axis: sum of all forces in y direction = m * a_y
So:
x axis:
x-component of Fn +...
It seems to me, that you are using inconsistent coordinate system.
If you say:
a = a_x = v^2/r, that means that you have chosen coordinate system in a such way, that radial inward acceleration is in the same plane as the road (ignore the effect of banking, but try to look at the road as a...
I really don't have much time because my college starts. I was trying a bit but I couldn't solve it. I guess I would need more time, or task is too difficult.
Try to ask on other places also. This is now a math problem, not physics, so consider asking math experts about these coordinate...
Hmmm...
First of all, we need to solve the logic problem you have mentioned at the bottom of your post. You see, I do believe in God, but still, I try to learn as much stuff as I can with a logical explanation, that is the way He created the world...
Ok...we need to know one thing. Consider following readings:
x = 0 g
y = 0 g
z = 3 g
You will say: "This is easy - device is in its regular position, and is suffering 1g from gravitation and 2 more Gs because of its acceleration..."
But I will tell you: "That's true. Partially. Because it CAN...
You could have taken the device in your hands looking at the display.
Call the:
front face - face A
back face - face B
right face - face C
left face - face D
top face - face E
bottom face - face F
Now you turn each face to be on bottom side of device (facing earth)
And by seeing the readings...
Hmmm. My mistake, it is not 1.4142 but 1/1.4142 (I multiplied instead of division)
I think that you use same data to feed in Ynew and Znew, but I could have made a mistake...
I will post later Insallah
I am sorry, but numeric solution doesn't help me, since I cannot analyze the data further that way, and I also don't think it's an easy task.
Maybe I am using a wrong approach.Here more description of my problem:
I have to change \theta from 0 to some value. While changing it my (green) curve...
Hmmm. I need distance of that intersection from the origin of the coordinate system. But I need it as a function of a \theta so I can find its minimal value for different \thetas . (i would have to use derivatives and other tricks later)
This is the picture of my problem for r = 5, R= 6 and D = 7.
Note that \theta is not visible on this picture, but it had a fixed value while I was taking the picture.
Making \theta change would cause curve to change position and orientation.
Thanks :D
Hi. I'd like to know whether is it possible to do the following, and if so, how...(and also, whether is it possible to solve similar problems)
I have parametric equation of a curve and I need to find its intersection with a ray that starts at the origin of the coordinate system and makes...
You need to use trigonometry if you want to make your transformations. In some special cases like 30, 45 or 60 degree tilt, you could get through with simple geometry.
First of all, when you tilt accelerometer by 45 degrees (rotation around x-axis), your readings will actually be: (0, 1.4142...