Yes. I actually came across "AAA" for the first time while applying to http://www.ox.ac.uk/admissions/undergraduate_courses/how_to_apply/index.html" (See under the heading "Late December 2008/January 2009". And please tell about "UCAS application". I have no idea about that.
I am unfamilier with the Grading System in UK.
What percentage of marks does 'A' and 'A*' corrospond to in the GCSE examinations?
And how much percentage of marks does 'AAA' corrospond to in the A levels. Great big thanks to any help.
:smile:
Then I suppose that the answer to the first question should be v-> c at very large times even although we cannot see it directly from the equation. I guess we need to derive another relativistic expression for very large times. Right! :smile:
Well I personally believe that the answer for acceleration makes sense. Initially the car might have acquired some velocity in a small time. I think the high acceleration is plausible.
For velocity, it cannot increase without bounds as velocity of a material object is limited by Relativity...
Another part of the question was:
Find the limiting value of the acceleration at very large and very
small times and comment on whether your results seem reason-
able.
On calaulating I got a=sqrt(p/2mt).
As t -> 0, a -> Infinity. Again That doesn't makes sense.
Homework Statement
This problem concerns the mathematical treatment of a simple model
of an electric toy car of mass m, which is initially stationary. The bat-
teries in the car can be considered as an electrical power source with
constant power P.
Find the limiting value of the...
I donno abt the rongs but i no the rights..
I think ans 1 is \sqrt{\frac{3\pi}{G \rho}}
& ans 2 =>> f= \frac{1}{2\pi}\sqrt{\frac{g (\frac{l}{2}-d)}{(\frac{l}{2}-d)^{2}+\frac{l^{2}}{12}}}
for f to be maximum d=\frac{l}{2\sqrt{3}}(\sqrt{3}-1)
Hi everyone! I too would like to request to have a solution to Zwiebach's Book and the solution to becker becker shwarz. My e-mail id is
lightspeedalice@yahoo.com