Here is my attempt:ƩF (for the block B) equals Fb - m2g = m2a ==> Fb = m2(a+g) ==> 40 = 4(a+9.8) ==> a=0.2 m/s2.
So, it closest to zero ( if i substitute g with value 10, a will be 0 ).
Is that correct ? or i should use the simple equation a = F/m ?
Homework Statement
Fig. 4.3
A 5.0-kg block and a 4.0-kg block are connected by a 0.6-kg rod. The links between the blocks and the rod are denoted by A and B. A force F is applied to the upper block.In Fig. 4.3, the force in link B is 40 N. The acceleration of the blocks and rod assembly...