okay, I think I've got it...
a)
h=50
v=200
a=9.8
t=?
h=(1/2)agt^2
50=(.5)(9.8)t^2
50=4.9t^2
√10.20 = √t^2
t=3.19s
b)r=?
R=vt
R=(200)(3.19)
R=638m
c) Horizontal motion is constant because there aren't...
Haha, I cannot draw worth a darn, but I will do my best. This is Exam Review, practice problems.
The direction of motion that's constant would be to horizontal, since the vertical changes when the missile declines?... As for the acceleration, it would be verticle? Being that it...
I do know that we are to use the equations of motion and...
displacement= (initial velocity)(change in time) + 1/2 (acceleration)(change in time)^2
But sadly, that's about it.
Physics doesn't come easily to me, I am more of a Literature/History minded individual, but I am here to...
HELP! Semester Exam on Monday!
Homework Statement
A missile is fired horizontally from an aircraft carrier in the ocean. Assuming the missile was shot from a height of 50m and a horizontal velocity of 200m/s...
a. How long is it in the air?
b. How far away will the missile land...