Recent content by alliegator

Thank you, you have saved me several hours of unnecessary work and frustration :D

Thank you so much. I can't believe I missed that, I can console myself with the fact that so has everyone else I have spoken to. So I used \dot{r}=0 and ended up with \frac{r^{2}}{a}=\frac{J\pm\sqrt{J^{2}-2gp^{2}/a}}{2mg} I'm guessing \frac{r^{2}}{a}=h Is this because in the original r the...

Homework Statement A particle of mass m moves on the surface of a paraboloidal bowl with position given by r=rcosθi+rsinθj+\frac{r^{2}}{a}k with a>0 constant. The particle is subject to a gravitational force F=-mgk but no other external forces. Show that a suitable Lagrangian for the system is...