Recent content by alw4026

Force = mass * acceleration

Okay I get that. Now what?

Okay, so it is just no longer in effect... Okay...

I'm just so confused on how a crate, with no legs/arms/feet/engine/force pushing it up, can be "sliding up" and incline.

Ohhh, okay, yes. I see. Now, that is an example where the object starts and stops, but this example is where it just says that the object is pushed up...

Can't I not find that, Net Force, until I find the fk (f sub k) or the kinetic friction.? Which is what I'm struggling to figure out..

The unknown force being Frictional, right? That's what I'm struggling with. I tried to do this: uk (mu sub k) = tan (theta) = tan (30 deg.) = 0.577350269 fk (f sub k) = uk (mu sub k) * FN (F sub N) = (0.577) * (51.96 N) = 29.99911999 The answer to the problem is 18 N, which is obviously not...

Yes. You would then be rolling backwards, so, negative.

I thought it was pretty straight-forward; I have attached it, though. Sorry.

https://scontent-dft4-1.xx.fbcdn.net/v/t35.0-12/14796269_10210868496286479_1115393743_o.jpg?oh=0ccd692c60a1d0bab84d5fbaf7e6197b&oe=580A1894 In the figure, a 6-kg box is sliding up an incline that makes an angle of theta=30 degree (with respect to the horizontal). As it slides up the incline, a...