Yeah, you're right, it is simpler to think of it as initial height=zero!
Is this right?
d= vv+1/2at^2
d= 0+1/2(10)(1.5^2)
d= 11.25m
So it does make the jump?
Well taking into consideration the previous problem where the car reaches 11.25m above the ramp, ie the initial starting point, and if the ramp is the same on the other side - that the car does not drop below 11.25m? That if the car drops below 11.25m then it would miss the ramp?
Conservation of energy? Energy cannot be created or destroyed, it may be transformed from one form into another, but the total amount of energy never changes? So in a closed system gravitation potential energy must equal kinetic energy and vice versa?
The formula that I have for GPE is
GPE= weight*height
But because I don't have the height, I can't see how to use this, and how to use energy conservation to relate the two points.
I am currently taking a 1st year introductory physics paper at university. I don't have a strong background in maths or science.
Homework Statement
A skateboarder with a total mass of 65kg is skating on a half-pipe ramp, as shown above. When he is at the bottom of the ramp he is traveling...
The last part of this question is -
Calculate whether the car will make the the jump if (the distance to the other side) d=55m?
I don't know how to do this question without knowing the height of the cliff the car is on, and the height that it has to reach on the other side. Does it have...