Recent content by amaliablachman

Whoops, I meant m^3! For the mass of the Milky Way, I did the mass of the sun (1.989 x10^30 kg) and then multiplied it by 50 billion, since the problem states that the mass of the Milky Way is 50 billion times the mass of the sun...right? Am I missing something there?

...and if that's the case, then the volume needed for intergalactic space to equal the mass of the Milky Way would have to be 5.9460543 x 10^67 cm3?

Would I just do v = m/d where m equals the mass of the Milky Way (9.9455 x 10^40) and d equals 1.67262178 × 10^-27 kg per cubic meter?

I know the mass of a single proton is 1.67262178 × 10^-27 kg...but I honestly have no idea where to go from here. I'm completely blank and just plugging things into the wrong places. I'm sure this is way simpler than I'm making it out to be in my head but it's 6:19 am, I have been doing this...

1. Most of the atoms in the universe are not in stars but in ionized gas in intergalactic space. The Milky Way has mass in its stars equivalent to 50 billion Suns (5 x 10^10 Msun). If the gas in the intergalactic medium only has a density of one proton per cubic meter, about how big a volume...