Recent content by Amamma1

  1. A

    Calculating Centripetal Force for Swinging Car Rear - 13.87 Feet Distance

    I really do appreciate your advice. I am just trying to come to term with the whole thing. I witnessed the whole thing with my own eyes and I do agree with you that "The rear of the decelerating car won't be moving in a circle." I know for a fact that the other car didn't move an inch laterally...
  2. A

    Calculating Centripetal Force for Swinging Car Rear - 13.87 Feet Distance

    Wow. I obviously was way off bases. One last question, was I correct in using the equation S=r.θ to calculate the length of the arc? Where the radius r=15 feet (the length of the 1999 Saturn). θ is the central angle, measured in radians, that is formed as the rear end of the Saturn swung from...
  3. A

    Calculating Centripetal Force for Swinging Car Rear - 13.87 Feet Distance

    Thank you very much for your reply. Thank you for correcting my use of the wrong terminology. But shouldn't this still leave some significant tell-Tale sign on the fiberglass skin of my bumper? Also, would it be possible that a 53 degree rotation of the entire car could take place yet without...
  4. A

    Calculating Centripetal Force for Swinging Car Rear - 13.87 Feet Distance

    Thank you very much for your help. Not too long ago I was involved in a very minor brush and go contact with another vehicle. I was driving a 1999 Dodge Ram 1500, which weighs about 4500 pounds. The other vehicle involved was a 1999 Saturn Sport Coupe, which is 15 feet long and it weighs 2400...
  5. A

    Calculating Centripetal Force for Swinging Car Rear - 13.87 Feet Distance

    What is the Centripetal Force needed to swing the rear end of a car a distance of 13.87 feet? The car is a front wheel drive, 15 feet long and it weighs 2400 pounds. Presumably, the front end of the car maintained its straight uphill path with a grade of 7% traveling at 40 m/h? The road pavement...
Back
Top