ok so i think i understand the problem but i can't find an apporpriate Psi(x,t=0) that will give me a constant PDF on the right side and zero PDF on the left? i tried looking at the website that Gokul mentioned but I'm confused by what they are trying to say..
i think i get it now...i need to first find a function Psi(x,t=0) whose modulus squared
|Psi(x,t=0)|^2 gives me zero for the left side and a constant for the right side...ok got that...i will try this onw...how about the probability of finding the electron in the ground state energy though...how...
we are told the the INITIALLY the electron is found in the right side of the infinite potential well...however as t>0 this does not have to be true...the electron can then be anywhere
i'm confused by what u are saying...still i would like some help on finding the ground state energy...thanx...
by the way guys this is the first time I'm using this site...thanx a lot in advance...the thing is I'm the only student in my quantum mechanics class so I have no one else to work with...
and i think the probability density function when t>0 should just look like a sin[n pi x/l)^2 graph..
ok so if you say that then i think that
Psi(x,t=0) = Sqrt(2/L) Sin(n pi x /L) for 0<=x<=L/2
and 0 for -L/2<=x<=0
but i don't know how to find the ground state energy now? I know that the probability density unction now would just be
|Psi(x,t)|^2 = (2/L) Sin(n pi x/ L)^2...
Homework Statement
Particle is in a tube with infinitely strong walls at x=-L/2 and x=L/2/ Suppose at t = 0 the electron known not to be in the left half of the tube, but you have no informations about where it might be in the right half---it is equally likely to be anywhere on the right side...