Recent content by AmK

I think i got it. i'll denote the length by l then ∠oxp by β and ∠xop by θ then l/sinθ = R/2sinβ ∫F.dr = ∫F*sinβ*Rdθ sinβ = (R/l)*sinθ ∫F*sinβ*Rdθ = ∫F*(R/l)*sinθ*Rdθ l=√R^2 + R^2/4 - R^2cosθ and then i can sub cosθ=t and range of t will be from 1 to -1 Thanks guys

Cosine formula for length PX and then sine formula for ∠ PXO That would make the integral very complex and i don't think i could solve that

Thanks Tiny-Tim the angle is what u said but for the integration i have to relate it to that angle to the angle subtended at the centre since the displacement would be in terms of that and i wasnt able to relate them

A small bead of mass m is moving on a smooth circular wire (radius R) under the action of a force F directed towards a point P at a distance R/2 from the centre .What should be the minimum velocity of the bead at the point where it is closest to P so that it may complete the circle. I worked it...