Recent content by ammora313

Thanks so much for your help and for being patient with me. You're awesome!

Ok so if I let Vi be negative: vf = -vi + at If I move vi to the other side it becomes 2v 2v=at 2v/a=t 2v/g=t is that correct?

It'll be traveling at 3 m/s when I catch it. I'm sorry I guess I meant they are proportional to each other but that would be wrong since they are equal with just opposite directions

Ok they are inversely proportional to each other since they are vectors

Are they inversely proportional to each other? Equal but opposite signs?

Oh ok sorry about that, I didn't know if that's where the 2v in the equation came from. If they're talking about the initial v and the v before it lands.

I'm trying to figure out how they came up with t=2v/g

Would the two velocities by equal? 2v?

the velocity before it lands is v=√2gh

I'm sorry that was a typo. The equation was v=v0 + at I was applying it to the whole process, from when the ball was thrown up to it landing

I'm sorry about that, I kept trying to make it right side up but it wouldn't budge. The one I need to determine is the time. The ones I know are acceleration (gravity) and velocity. There is the equation v=v0 + 1/2 at2 but I'm not sure how to manipulate it to come out to t=2v/g. When I tried...

Homework Statement t=2v/g the AAMC used this formula to solve a problem that was asking what would happen to time if the gravity becomes g/6. the answer is that the time increases by a factor of 6. Homework Equations v=v0 + at The Attempt at a Solution I got the wrong answer by thinking...

Reaction: C6H8O6 + I3- +H2O ↔ C6H6O6 +3I- +2H3O+ Stoichiometry is one to one. So 9.40 mL of 0.015 M titrant contains 1.41x10^-4 mol I3-. Since it's a 1:1, 25mL aliquot contains 1.41x10^-4 moles vitamin C. There are 10 25mL in 250 mL so 10 x 1.41x10^-4 moles = 1.41 x 10^-3 moles 1.41x10^-3...

Ok I figured it out, thanks for being patient with me. So since the stoichiometry is one to one, it takes 4.258 x 10-4 mol of triiodide to react with the same number of moles of ascorbic acid. then using v=n/c, it takes 28.3 mL of triiodide. :approve: