@BiGyElLoWhAt I was hoping you might take a look at this problem and see if it looks right. According to the answer key my professor sent out today, the velocity is correct but the acceleration is not. My professor has a=80.04m/s^2
I think I've solved it with the kinematics equations, but the problem is part of a practice test and my professor wants me to show my work using calculus for all problems. I'm so confused.
I haven't taken calculus in 5 years, so I don't really think I would say I know calculus haha how would I derive the vector position function you're talking about?
Homework Statement
I've attached a picture of the problem
Homework Equations
I'm assuming I need to use ads=vdv
The Attempt at a Solution
I've attached a picture of my attempt at solving the problem, but I really have no idea what I'm doing. I'm really having a hard time in this...
So (.05*9.81*-2) - (.02*9.81*2) = -.5886
But you said: Your -0.5886 number has the right magnitude for the net change in PE. Note that the change in KE must have the opposite sign, since what's lost in PE results in a gain in KE.
So that sounds like it shouldn't be -.5886, but instead .5886?
Uim1 = .05*9.81*2 = .981
Uim2 = .02*9.81*2 = .3924
Ufm1 = .02*9.81*0 = 0
Ufm2 = .02*9.81*4 = .7848
ΔU = Uf-Ui = ?
For the final PE calculations should I be using Δh (m1= -2/m2= +2) instead of h (m1= 0/m2= 4)?
That just made me even more unsure of what I'm doing. I appreciate your help so much, is there anyway to "dumb it down" further? I have been working on this problem for hours I'm getting so frustrated.
ΔU=-0.7848-1.3734=-2.1582 and looking at that it seems like that's way too big of a difference. Should I switch the positive direction of motion? So that I have ΔU=0.7848-1.3734=-0.5886 that seems much more likely to me? Oh man I'm so confused by this